# How to check whether a number is an Armstrong number or not in java?

A special positive number whose sum of cubes of its individual digit is equal to that number is called an Armstrong Number

Example #1,
The number 153 is an Armstrong number. It can be checked as follow:
(1)3 + (5)3 + (3)3 => 1 + 125 + 27 => 153

Example #2,
The number 371 is also an Armstrong number and It can be checked as follow:
(3)3 + (7)3 + (1)3 => 27 + 343 + 1 => 371

Let’s see the logic to check whether a number is an Armstrong number or not,

### Armstrong number in java

ArmstrongNumber.java

```package com.javacodepoint.programs;

import java.util.Scanner;

public class ArmstrongNumber {

public static void main(String[] args) {

// Taking input from the user to check whether number is Armstrong

System.out.println("Enter a number to check Armstrong :");

// Reading user input using Scanner object
int number = new Scanner(System.in).nextInt();

if(checkArmstrong(number)) {
System.out.println("The given number is an Armstrong number.");
}else {
System.out.println("The given number is not an Armstrong number.");
}

}

/*
* Method to check Armstrong number
*/
public static boolean checkArmstrong(int number) {

int sumOfCube = 0;
int temp = number;
while(number > 0){

//Getting last digit
int a = number % 10;

//Removing last digit from number
number = number / 10;

//Calculating sum of cubes of digits
sumOfCube = sumOfCube + (a*a*a);
}

if(temp == sumOfCube) {
return true;
}

return false;
}

}

```

OUTPUT:

Enter a number to check Armstrong :
370
The given number is an Armstrong number.